1.2=-16t^2+19t+5

Solution for 1.2=-16t^2+19t+5 equation:

1.2=-16t^2+19t+5

We move all terms to the left:

1.2-(-16t^2+19t+5)=0

We get rid of parentheses

16t^2-19t-5+1.2=0

We add all the numbers together, and all the variables

16t^2-19t-3.8=0

a = 16; b = -19; c = -3.8;
Δ = b2-4ac
Δ = -192-4·16·(-3.8)
Δ = 604.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{604.2}}{2*16}=\frac{19-\sqrt{604.2}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{604.2}}{2*16}=\frac{19+\sqrt{604.2}}{32}
$